3.24.81 \(\int \frac {1}{(d+e x)^4 \sqrt {a+b x+c x^2}} \, dx\) [2381]

Optimal. Leaf size=293 \[ -\frac {e \sqrt {a+b x+c x^2}}{3 \left (c d^2-b d e+a e^2\right ) (d+e x)^3}-\frac {5 e (2 c d-b e) \sqrt {a+b x+c x^2}}{12 \left (c d^2-b d e+a e^2\right )^2 (d+e x)^2}-\frac {e \left (44 c^2 d^2+15 b^2 e^2-4 c e (11 b d+4 a e)\right ) \sqrt {a+b x+c x^2}}{24 \left (c d^2-b d e+a e^2\right )^3 (d+e x)}+\frac {(2 c d-b e) \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \tanh ^{-1}\left (\frac {b d-2 a e+(2 c d-b e) x}{2 \sqrt {c d^2-b d e+a e^2} \sqrt {a+b x+c x^2}}\right )}{16 \left (c d^2-b d e+a e^2\right )^{7/2}} \]

[Out]

1/16*(-b*e+2*c*d)*(8*c^2*d^2+5*b^2*e^2-4*c*e*(3*a*e+2*b*d))*arctanh(1/2*(b*d-2*a*e+(-b*e+2*c*d)*x)/(a*e^2-b*d*
e+c*d^2)^(1/2)/(c*x^2+b*x+a)^(1/2))/(a*e^2-b*d*e+c*d^2)^(7/2)-1/3*e*(c*x^2+b*x+a)^(1/2)/(a*e^2-b*d*e+c*d^2)/(e
*x+d)^3-5/12*e*(-b*e+2*c*d)*(c*x^2+b*x+a)^(1/2)/(a*e^2-b*d*e+c*d^2)^2/(e*x+d)^2-1/24*e*(44*c^2*d^2+15*b^2*e^2-
4*c*e*(4*a*e+11*b*d))*(c*x^2+b*x+a)^(1/2)/(a*e^2-b*d*e+c*d^2)^3/(e*x+d)

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Rubi [A]
time = 0.23, antiderivative size = 293, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {758, 848, 820, 738, 212} \begin {gather*} -\frac {e \sqrt {a+b x+c x^2} \left (-4 c e (4 a e+11 b d)+15 b^2 e^2+44 c^2 d^2\right )}{24 (d+e x) \left (a e^2-b d e+c d^2\right )^3}+\frac {(2 c d-b e) \left (-4 c e (3 a e+2 b d)+5 b^2 e^2+8 c^2 d^2\right ) \tanh ^{-1}\left (\frac {-2 a e+x (2 c d-b e)+b d}{2 \sqrt {a+b x+c x^2} \sqrt {a e^2-b d e+c d^2}}\right )}{16 \left (a e^2-b d e+c d^2\right )^{7/2}}-\frac {5 e \sqrt {a+b x+c x^2} (2 c d-b e)}{12 (d+e x)^2 \left (a e^2-b d e+c d^2\right )^2}-\frac {e \sqrt {a+b x+c x^2}}{3 (d+e x)^3 \left (a e^2-b d e+c d^2\right )} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/((d + e*x)^4*Sqrt[a + b*x + c*x^2]),x]

[Out]

-1/3*(e*Sqrt[a + b*x + c*x^2])/((c*d^2 - b*d*e + a*e^2)*(d + e*x)^3) - (5*e*(2*c*d - b*e)*Sqrt[a + b*x + c*x^2
])/(12*(c*d^2 - b*d*e + a*e^2)^2*(d + e*x)^2) - (e*(44*c^2*d^2 + 15*b^2*e^2 - 4*c*e*(11*b*d + 4*a*e))*Sqrt[a +
b*x + c*x^2])/(24*(c*d^2 - b*d*e + a*e^2)^3*(d + e*x)) + ((2*c*d - b*e)*(8*c^2*d^2 + 5*b^2*e^2 - 4*c*e*(2*b*d
+ 3*a*e))*ArcTanh[(b*d - 2*a*e + (2*c*d - b*e)*x)/(2*Sqrt[c*d^2 - b*d*e + a*e^2]*Sqrt[a + b*x + c*x^2])])/(16
*(c*d^2 - b*d*e + a*e^2)^(7/2))

Rule 212

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))*ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 738

Int[1/(((d_.) + (e_.)*(x_))*Sqrt[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2]), x_Symbol] :> Dist[-2, Subst[Int[1/(4*c*d
^2 - 4*b*d*e + 4*a*e^2 - x^2), x], x, (2*a*e - b*d - (2*c*d - b*e)*x)/Sqrt[a + b*x + c*x^2]], x] /; FreeQ[{a,
b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[2*c*d - b*e, 0]

Rule 758

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[e*(d + e*x)^(m + 1)*
((a + b*x + c*x^2)^(p + 1)/((m + 1)*(c*d^2 - b*d*e + a*e^2))), x] + Dist[1/((m + 1)*(c*d^2 - b*d*e + a*e^2)),
Int[(d + e*x)^(m + 1)*Simp[c*d*(m + 1) - b*e*(m + p + 2) - c*e*(m + 2*p + 3)*x, x]*(a + b*x + c*x^2)^p, x], x]
/; FreeQ[{a, b, c, d, e, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && NeQ[2*c*d - b*e
, 0] && NeQ[m, -1] && ((LtQ[m, -1] && IntQuadraticQ[a, b, c, d, e, m, p, x]) || (SumSimplerQ[m, 1] && IntegerQ
[p]) || ILtQ[Simplify[m + 2*p + 3], 0])

Rule 820

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Sim
p[(-(e*f - d*g))*(d + e*x)^(m + 1)*((a + b*x + c*x^2)^(p + 1)/(2*(p + 1)*(c*d^2 - b*d*e + a*e^2))), x] - Dist[
(b*(e*f + d*g) - 2*(c*d*f + a*e*g))/(2*(c*d^2 - b*d*e + a*e^2)), Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p, x]
, x] /; FreeQ[{a, b, c, d, e, f, g, m, p}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && EqQ[S
implify[m + 2*p + 3], 0]

Rule 848

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Sim
p[(e*f - d*g)*(d + e*x)^(m + 1)*((a + b*x + c*x^2)^(p + 1)/((m + 1)*(c*d^2 - b*d*e + a*e^2))), x] + Dist[1/((m
+ 1)*(c*d^2 - b*d*e + a*e^2)), Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p*Simp[(c*d*f - f*b*e + a*e*g)*(m + 1)
+ b*(d*g - e*f)*(p + 1) - c*(e*f - d*g)*(m + 2*p + 3)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, g, p}, x] &&
NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && LtQ[m, -1] && (IntegerQ[m] || IntegerQ[p] || IntegersQ
[2*m, 2*p])

Rubi steps

\begin {align*} \int \frac {1}{(d+e x)^4 \sqrt {a+b x+c x^2}} \, dx &=-\frac {e \sqrt {a+b x+c x^2}}{3 \left (c d^2-b d e+a e^2\right ) (d+e x)^3}-\frac {\int \frac {\frac {1}{2} (-6 c d+5 b e)+2 c e x}{(d+e x)^3 \sqrt {a+b x+c x^2}} \, dx}{3 \left (c d^2-b d e+a e^2\right )}\\ &=-\frac {e \sqrt {a+b x+c x^2}}{3 \left (c d^2-b d e+a e^2\right ) (d+e x)^3}-\frac {5 e (2 c d-b e) \sqrt {a+b x+c x^2}}{12 \left (c d^2-b d e+a e^2\right )^2 (d+e x)^2}+\frac {\int \frac {\frac {1}{4} \left (24 c^2 d^2+15 b^2 e^2-2 c e (17 b d+8 a e)\right )-\frac {5}{2} c e (2 c d-b e) x}{(d+e x)^2 \sqrt {a+b x+c x^2}} \, dx}{6 \left (c d^2-b d e+a e^2\right )^2}\\ &=-\frac {e \sqrt {a+b x+c x^2}}{3 \left (c d^2-b d e+a e^2\right ) (d+e x)^3}-\frac {5 e (2 c d-b e) \sqrt {a+b x+c x^2}}{12 \left (c d^2-b d e+a e^2\right )^2 (d+e x)^2}-\frac {e \left (44 c^2 d^2+15 b^2 e^2-4 c e (11 b d+4 a e)\right ) \sqrt {a+b x+c x^2}}{24 \left (c d^2-b d e+a e^2\right )^3 (d+e x)}+\frac {\left ((2 c d-b e) \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right )\right ) \int \frac {1}{(d+e x) \sqrt {a+b x+c x^2}} \, dx}{16 \left (c d^2-b d e+a e^2\right )^3}\\ &=-\frac {e \sqrt {a+b x+c x^2}}{3 \left (c d^2-b d e+a e^2\right ) (d+e x)^3}-\frac {5 e (2 c d-b e) \sqrt {a+b x+c x^2}}{12 \left (c d^2-b d e+a e^2\right )^2 (d+e x)^2}-\frac {e \left (44 c^2 d^2+15 b^2 e^2-4 c e (11 b d+4 a e)\right ) \sqrt {a+b x+c x^2}}{24 \left (c d^2-b d e+a e^2\right )^3 (d+e x)}-\frac {\left ((2 c d-b e) \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right )\right ) \text {Subst}\left (\int \frac {1}{4 c d^2-4 b d e+4 a e^2-x^2} \, dx,x,\frac {-b d+2 a e-(2 c d-b e) x}{\sqrt {a+b x+c x^2}}\right )}{8 \left (c d^2-b d e+a e^2\right )^3}\\ &=-\frac {e \sqrt {a+b x+c x^2}}{3 \left (c d^2-b d e+a e^2\right ) (d+e x)^3}-\frac {5 e (2 c d-b e) \sqrt {a+b x+c x^2}}{12 \left (c d^2-b d e+a e^2\right )^2 (d+e x)^2}-\frac {e \left (44 c^2 d^2+15 b^2 e^2-4 c e (11 b d+4 a e)\right ) \sqrt {a+b x+c x^2}}{24 \left (c d^2-b d e+a e^2\right )^3 (d+e x)}+\frac {(2 c d-b e) \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \tanh ^{-1}\left (\frac {b d-2 a e+(2 c d-b e) x}{2 \sqrt {c d^2-b d e+a e^2} \sqrt {a+b x+c x^2}}\right )}{16 \left (c d^2-b d e+a e^2\right )^{7/2}}\\ \end {align*}

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Mathematica [A]
time = 10.41, size = 288, normalized size = 0.98 \begin {gather*} -\frac {\frac {2 e \left (c d^2+e (-b d+a e)\right ) \sqrt {a+x (b+c x)}}{(d+e x)^3}+\frac {5 e (2 c d-b e) \sqrt {a+x (b+c x)}}{2 (d+e x)^2}+\frac {e \left (44 c^2 d^2+15 b^2 e^2-4 c e (11 b d+4 a e)\right ) \sqrt {a+x (b+c x)}}{4 \left (c d^2+e (-b d+a e)\right ) (d+e x)}+\frac {3 (2 c d-b e) \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) \tanh ^{-1}\left (\frac {-b d+2 a e-2 c d x+b e x}{2 \sqrt {c d^2+e (-b d+a e)} \sqrt {a+x (b+c x)}}\right )}{8 \left (c d^2+e (-b d+a e)\right )^{3/2}}}{6 \left (c d^2+e (-b d+a e)\right )^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/((d + e*x)^4*Sqrt[a + b*x + c*x^2]),x]

[Out]

-1/6*((2*e*(c*d^2 + e*(-(b*d) + a*e))*Sqrt[a + x*(b + c*x)])/(d + e*x)^3 + (5*e*(2*c*d - b*e)*Sqrt[a + x*(b +
c*x)])/(2*(d + e*x)^2) + (e*(44*c^2*d^2 + 15*b^2*e^2 - 4*c*e*(11*b*d + 4*a*e))*Sqrt[a + x*(b + c*x)])/(4*(c*d^
2 + e*(-(b*d) + a*e))*(d + e*x)) + (3*(2*c*d - b*e)*(8*c^2*d^2 + 5*b^2*e^2 - 4*c*e*(2*b*d + 3*a*e))*ArcTanh[(-
(b*d) + 2*a*e - 2*c*d*x + b*e*x)/(2*Sqrt[c*d^2 + e*(-(b*d) + a*e)]*Sqrt[a + x*(b + c*x)])])/(8*(c*d^2 + e*(-(b
*d) + a*e))^(3/2)))/(c*d^2 + e*(-(b*d) + a*e))^2

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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(965\) vs. \(2(271)=542\).
time = 0.81, size = 966, normalized size = 3.30

method	result	size
default	\(\frac {-\frac {e^{2} \sqrt {c \left (x +\frac {d}{e}\right )^{2}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}{3 \left (e^{2} a -b d e +c \,d^{2}\right ) \left (x +\frac {d}{e}\right )^{3}}-\frac {5 e \left (b e -2 c d \right ) \left (-\frac {e^{2} \sqrt {c \left (x +\frac {d}{e}\right )^{2}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}{2 \left (e^{2} a -b d e +c \,d^{2}\right ) \left (x +\frac {d}{e}\right )^{2}}-\frac {3 e \left (b e -2 c d \right ) \left (-\frac {e^{2} \sqrt {c \left (x +\frac {d}{e}\right )^{2}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}{\left (e^{2} a -b d e +c \,d^{2}\right ) \left (x +\frac {d}{e}\right )}+\frac {e \left (b e -2 c d \right ) \ln \left (\frac {\frac {2 e^{2} a -2 b d e +2 c \,d^{2}}{e^{2}}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+2 \sqrt {\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}\, \sqrt {c \left (x +\frac {d}{e}\right )^{2}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}{x +\frac {d}{e}}\right )}{2 \left (e^{2} a -b d e +c \,d^{2}\right ) \sqrt {\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}\right )}{4 \left (e^{2} a -b d e +c \,d^{2}\right )}+\frac {c \,e^{2} \ln \left (\frac {\frac {2 e^{2} a -2 b d e +2 c \,d^{2}}{e^{2}}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+2 \sqrt {\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}\, \sqrt {c \left (x +\frac {d}{e}\right )^{2}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}{x +\frac {d}{e}}\right )}{2 \left (e^{2} a -b d e +c \,d^{2}\right ) \sqrt {\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}\right )}{6 \left (e^{2} a -b d e +c \,d^{2}\right )}-\frac {2 c \,e^{2} \left (-\frac {e^{2} \sqrt {c \left (x +\frac {d}{e}\right )^{2}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}{\left (e^{2} a -b d e +c \,d^{2}\right ) \left (x +\frac {d}{e}\right )}+\frac {e \left (b e -2 c d \right ) \ln \left (\frac {\frac {2 e^{2} a -2 b d e +2 c \,d^{2}}{e^{2}}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+2 \sqrt {\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}\, \sqrt {c \left (x +\frac {d}{e}\right )^{2}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}{x +\frac {d}{e}}\right )}{2 \left (e^{2} a -b d e +c \,d^{2}\right ) \sqrt {\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}\right )}{3 \left (e^{2} a -b d e +c \,d^{2}\right )}}{e^{4}}\)	\(966\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(e*x+d)^4/(c*x^2+b*x+a)^(1/2),x,method=_RETURNVERBOSE)

[Out]

1/e^4*(-1/3/(a*e^2-b*d*e+c*d^2)*e^2/(x+d/e)^3*(c*(x+d/e)^2+1/e*(b*e-2*c*d)*(x+d/e)+(a*e^2-b*d*e+c*d^2)/e^2)^(1
/2)-5/6*e*(b*e-2*c*d)/(a*e^2-b*d*e+c*d^2)*(-1/2/(a*e^2-b*d*e+c*d^2)*e^2/(x+d/e)^2*(c*(x+d/e)^2+1/e*(b*e-2*c*d)
*(x+d/e)+(a*e^2-b*d*e+c*d^2)/e^2)^(1/2)-3/4*e*(b*e-2*c*d)/(a*e^2-b*d*e+c*d^2)*(-1/(a*e^2-b*d*e+c*d^2)*e^2/(x+d
/e)*(c*(x+d/e)^2+1/e*(b*e-2*c*d)*(x+d/e)+(a*e^2-b*d*e+c*d^2)/e^2)^(1/2)+1/2*e*(b*e-2*c*d)/(a*e^2-b*d*e+c*d^2)/
((a*e^2-b*d*e+c*d^2)/e^2)^(1/2)*ln((2*(a*e^2-b*d*e+c*d^2)/e^2+1/e*(b*e-2*c*d)*(x+d/e)+2*((a*e^2-b*d*e+c*d^2)/e
^2)^(1/2)*(c*(x+d/e)^2+1/e*(b*e-2*c*d)*(x+d/e)+(a*e^2-b*d*e+c*d^2)/e^2)^(1/2))/(x+d/e)))+1/2*c/(a*e^2-b*d*e+c*
d^2)*e^2/((a*e^2-b*d*e+c*d^2)/e^2)^(1/2)*ln((2*(a*e^2-b*d*e+c*d^2)/e^2+1/e*(b*e-2*c*d)*(x+d/e)+2*((a*e^2-b*d*e
+c*d^2)/e^2)^(1/2)*(c*(x+d/e)^2+1/e*(b*e-2*c*d)*(x+d/e)+(a*e^2-b*d*e+c*d^2)/e^2)^(1/2))/(x+d/e)))-2/3*c/(a*e^2
-b*d*e+c*d^2)*e^2*(-1/(a*e^2-b*d*e+c*d^2)*e^2/(x+d/e)*(c*(x+d/e)^2+1/e*(b*e-2*c*d)*(x+d/e)+(a*e^2-b*d*e+c*d^2)
/e^2)^(1/2)+1/2*e*(b*e-2*c*d)/(a*e^2-b*d*e+c*d^2)/((a*e^2-b*d*e+c*d^2)/e^2)^(1/2)*ln((2*(a*e^2-b*d*e+c*d^2)/e^
2+1/e*(b*e-2*c*d)*(x+d/e)+2*((a*e^2-b*d*e+c*d^2)/e^2)^(1/2)*(c*(x+d/e)^2+1/e*(b*e-2*c*d)*(x+d/e)+(a*e^2-b*d*e+
c*d^2)/e^2)^(1/2))/(x+d/e))))

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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^4/(c*x^2+b*x+a)^(1/2),x, algorithm="maxima")

[Out]

Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'a
ssume' command before evaluation *may* help (example of legal syntax is 'assume(c*d^2-%e*b*d+%e^2*a>0)', see `
assume?` for

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 1312 vs. \(2 (283) = 566\).
time = 17.27, size = 2667, normalized size = 9.10 \begin {gather*} \text {Too large to display} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^4/(c*x^2+b*x+a)^(1/2),x, algorithm="fricas")

[Out]

[1/96*(3*(16*c^3*d^6 - (5*b^3 - 12*a*b*c)*x^3*e^6 + 3*(2*(3*b^2*c - 4*a*c^2)*d*x^3 - (5*b^3 - 12*a*b*c)*d*x^2)
*e^5 - 3*(8*b*c^2*d^2*x^3 - 6*(3*b^2*c - 4*a*c^2)*d^2*x^2 + (5*b^3 - 12*a*b*c)*d^2*x)*e^4 + (16*c^3*d^3*x^3 -
72*b*c^2*d^3*x^2 + 18*(3*b^2*c - 4*a*c^2)*d^3*x - (5*b^3 - 12*a*b*c)*d^3)*e^3 + 6*(8*c^3*d^4*x^2 - 12*b*c^2*d^
4*x + (3*b^2*c - 4*a*c^2)*d^4)*e^2 + 24*(2*c^3*d^5*x - b*c^2*d^5)*e)*sqrt(c*d^2 - b*d*e + a*e^2)*log(-(8*c^2*d
^2*x^2 + 8*b*c*d^2*x + (b^2 + 4*a*c)*d^2 + 4*sqrt(c*d^2 - b*d*e + a*e^2)*(2*c*d*x + b*d - (b*x + 2*a)*e)*sqrt(
c*x^2 + b*x + a) + (8*a*b*x + (b^2 + 4*a*c)*x^2 + 8*a^2)*e^2 - 2*(4*b*c*d*x^2 + 4*a*b*d + (3*b^2 + 4*a*c)*d*x)
*e)/(x^2*e^2 + 2*d*x*e + d^2)) - 4*(72*c^3*d^6*e - (10*a^2*b*x - 8*a^3 - (15*a*b^2 - 16*a^2*c)*x^2)*e^7 - (34*
a^2*b*d + (15*b^3 + 28*a*b*c)*d*x^2 - 2*(25*a*b^2 - 6*a^2*c)*d*x)*e^6 + ((59*b^2*c + 28*a*c^2)*d^2*x^2 - 4*(10
*b^3 + 29*a*b*c)*d^2*x + (59*a*b^2 + 28*a^2*c)*d^2)*e^5 - (88*b*c^2*d^3*x^2 - 2*(79*b^2*c + 48*a*c^2)*d^3*x +
(33*b^3 + 136*a*b*c)*d^3)*e^4 + (44*c^3*d^4*x^2 - 226*b*c^2*d^4*x + (123*b^2*c + 92*a*c^2)*d^4)*e^3 + 54*(2*c^
3*d^5*x - 3*b*c^2*d^5)*e^2)*sqrt(c*x^2 + b*x + a))/(c^4*d^11 + a^4*x^3*e^11 - (4*a^3*b*d*x^3 - 3*a^4*d*x^2)*e^
10 - (12*a^3*b*d^2*x^2 - 3*a^4*d^2*x - 2*(3*a^2*b^2 + 2*a^3*c)*d^2*x^3)*e^9 - (12*a^3*b*d^3*x - a^4*d^3 + 4*(a
*b^3 + 3*a^2*b*c)*d^3*x^3 - 6*(3*a^2*b^2 + 2*a^3*c)*d^3*x^2)*e^8 - (4*a^3*b*d^4 - (b^4 + 12*a*b^2*c + 6*a^2*c^
2)*d^4*x^3 + 12*(a*b^3 + 3*a^2*b*c)*d^4*x^2 - 6*(3*a^2*b^2 + 2*a^3*c)*d^4*x)*e^7 - (4*(b^3*c + 3*a*b*c^2)*d^5*
x^3 - 3*(b^4 + 12*a*b^2*c + 6*a^2*c^2)*d^5*x^2 + 12*(a*b^3 + 3*a^2*b*c)*d^5*x - 2*(3*a^2*b^2 + 2*a^3*c)*d^5)*e
^6 + (2*(3*b^2*c^2 + 2*a*c^3)*d^6*x^3 - 12*(b^3*c + 3*a*b*c^2)*d^6*x^2 + 3*(b^4 + 12*a*b^2*c + 6*a^2*c^2)*d^6*
x - 4*(a*b^3 + 3*a^2*b*c)*d^6)*e^5 - (4*b*c^3*d^7*x^3 - 6*(3*b^2*c^2 + 2*a*c^3)*d^7*x^2 + 12*(b^3*c + 3*a*b*c^
2)*d^7*x - (b^4 + 12*a*b^2*c + 6*a^2*c^2)*d^7)*e^4 + (c^4*d^8*x^3 - 12*b*c^3*d^8*x^2 + 6*(3*b^2*c^2 + 2*a*c^3)
*d^8*x - 4*(b^3*c + 3*a*b*c^2)*d^8)*e^3 + (3*c^4*d^9*x^2 - 12*b*c^3*d^9*x + 2*(3*b^2*c^2 + 2*a*c^3)*d^9)*e^2 +
(3*c^4*d^10*x - 4*b*c^3*d^10)*e), 1/48*(3*(16*c^3*d^6 - (5*b^3 - 12*a*b*c)*x^3*e^6 + 3*(2*(3*b^2*c - 4*a*c^2)
*d*x^3 - (5*b^3 - 12*a*b*c)*d*x^2)*e^5 - 3*(8*b*c^2*d^2*x^3 - 6*(3*b^2*c - 4*a*c^2)*d^2*x^2 + (5*b^3 - 12*a*b*
c)*d^2*x)*e^4 + (16*c^3*d^3*x^3 - 72*b*c^2*d^3*x^2 + 18*(3*b^2*c - 4*a*c^2)*d^3*x - (5*b^3 - 12*a*b*c)*d^3)*e^
3 + 6*(8*c^3*d^4*x^2 - 12*b*c^2*d^4*x + (3*b^2*c - 4*a*c^2)*d^4)*e^2 + 24*(2*c^3*d^5*x - b*c^2*d^5)*e)*sqrt(-c
*d^2 + b*d*e - a*e^2)*arctan(-1/2*sqrt(-c*d^2 + b*d*e - a*e^2)*(2*c*d*x + b*d - (b*x + 2*a)*e)*sqrt(c*x^2 + b*
x + a)/(c^2*d^2*x^2 + b*c*d^2*x + a*c*d^2 + (a*c*x^2 + a*b*x + a^2)*e^2 - (b*c*d*x^2 + b^2*d*x + a*b*d)*e)) -
2*(72*c^3*d^6*e - (10*a^2*b*x - 8*a^3 - (15*a*b^2 - 16*a^2*c)*x^2)*e^7 - (34*a^2*b*d + (15*b^3 + 28*a*b*c)*d*x
^2 - 2*(25*a*b^2 - 6*a^2*c)*d*x)*e^6 + ((59*b^2*c + 28*a*c^2)*d^2*x^2 - 4*(10*b^3 + 29*a*b*c)*d^2*x + (59*a*b^
2 + 28*a^2*c)*d^2)*e^5 - (88*b*c^2*d^3*x^2 - 2*(79*b^2*c + 48*a*c^2)*d^3*x + (33*b^3 + 136*a*b*c)*d^3)*e^4 + (
44*c^3*d^4*x^2 - 226*b*c^2*d^4*x + (123*b^2*c + 92*a*c^2)*d^4)*e^3 + 54*(2*c^3*d^5*x - 3*b*c^2*d^5)*e^2)*sqrt(
c*x^2 + b*x + a))/(c^4*d^11 + a^4*x^3*e^11 - (4*a^3*b*d*x^3 - 3*a^4*d*x^2)*e^10 - (12*a^3*b*d^2*x^2 - 3*a^4*d^
2*x - 2*(3*a^2*b^2 + 2*a^3*c)*d^2*x^3)*e^9 - (12*a^3*b*d^3*x - a^4*d^3 + 4*(a*b^3 + 3*a^2*b*c)*d^3*x^3 - 6*(3*
a^2*b^2 + 2*a^3*c)*d^3*x^2)*e^8 - (4*a^3*b*d^4 - (b^4 + 12*a*b^2*c + 6*a^2*c^2)*d^4*x^3 + 12*(a*b^3 + 3*a^2*b*
c)*d^4*x^2 - 6*(3*a^2*b^2 + 2*a^3*c)*d^4*x)*e^7 - (4*(b^3*c + 3*a*b*c^2)*d^5*x^3 - 3*(b^4 + 12*a*b^2*c + 6*a^2
*c^2)*d^5*x^2 + 12*(a*b^3 + 3*a^2*b*c)*d^5*x - 2*(3*a^2*b^2 + 2*a^3*c)*d^5)*e^6 + (2*(3*b^2*c^2 + 2*a*c^3)*d^6
*x^3 - 12*(b^3*c + 3*a*b*c^2)*d^6*x^2 + 3*(b^4 + 12*a*b^2*c + 6*a^2*c^2)*d^6*x - 4*(a*b^3 + 3*a^2*b*c)*d^6)*e^
5 - (4*b*c^3*d^7*x^3 - 6*(3*b^2*c^2 + 2*a*c^3)*d^7*x^2 + 12*(b^3*c + 3*a*b*c^2)*d^7*x - (b^4 + 12*a*b^2*c + 6*
a^2*c^2)*d^7)*e^4 + (c^4*d^8*x^3 - 12*b*c^3*d^8*x^2 + 6*(3*b^2*c^2 + 2*a*c^3)*d^8*x - 4*(b^3*c + 3*a*b*c^2)*d^
8)*e^3 + (3*c^4*d^9*x^2 - 12*b*c^3*d^9*x + 2*(3*b^2*c^2 + 2*a*c^3)*d^9)*e^2 + (3*c^4*d^10*x - 4*b*c^3*d^10)*e)
]

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (d + e x\right )^{4} \sqrt {a + b x + c x^{2}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)**4/(c*x**2+b*x+a)**(1/2),x)

[Out]

Integral(1/((d + e*x)**4*sqrt(a + b*x + c*x**2)), x)

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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 2079 vs. \(2 (283) = 566\).
time = 2.82, size = 2079, normalized size = 7.10 \begin {gather*} \text {Too large to display} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^4/(c*x^2+b*x+a)^(1/2),x, algorithm="giac")

[Out]

1/8*(16*c^3*d^3 - 24*b*c^2*d^2*e + 18*b^2*c*d*e^2 - 24*a*c^2*d*e^2 - 5*b^3*e^3 + 12*a*b*c*e^3)*arctan(-((sqrt(
c)*x - sqrt(c*x^2 + b*x + a))*e + sqrt(c)*d)/sqrt(-c*d^2 + b*d*e - a*e^2))/((c^3*d^6 - 3*b*c^2*d^5*e + 3*b^2*c
*d^4*e^2 + 3*a*c^2*d^4*e^2 - b^3*d^3*e^3 - 6*a*b*c*d^3*e^3 + 3*a*b^2*d^2*e^4 + 3*a^2*c*d^2*e^4 - 3*a^2*b*d*e^5
+ a^3*e^6)*sqrt(-c*d^2 + b*d*e - a*e^2)) - 1/24*(240*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^4*c^(7/2)*d^4*e + 35
2*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^3*c^4*d^5 + 48*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^5*c^3*d^3*e^2 - 400*(
sqrt(c)*x - sqrt(c*x^2 + b*x + a))^3*b*c^3*d^4*e + 528*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2*b*c^(7/2)*d^5 - 3
60*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^4*b*c^(5/2)*d^3*e^2 - 756*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2*b^2*c^(
5/2)*d^4*e - 816*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2*a*c^(7/2)*d^4*e + 264*(sqrt(c)*x - sqrt(c*x^2 + b*x + a
))*b^2*c^3*d^5 - 72*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^5*b*c^2*d^2*e^3 + 204*(sqrt(c)*x - sqrt(c*x^2 + b*x +
a))^3*b^2*c^2*d^3*e^2 - 656*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^3*a*c^3*d^3*e^2 - 336*(sqrt(c)*x - sqrt(c*x^2
+ b*x + a))*b^3*c^2*d^4*e - 816*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))*a*b*c^3*d^4*e + 44*b^3*c^(5/2)*d^5 + 270*(
sqrt(c)*x - sqrt(c*x^2 + b*x + a))^4*b^2*c^(3/2)*d^2*e^3 - 360*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^4*a*c^(5/2)
*d^2*e^3 + 498*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2*b^3*c^(3/2)*d^3*e^2 + 648*(sqrt(c)*x - sqrt(c*x^2 + b*x +
a))^2*a*b*c^(5/2)*d^3*e^2 - 44*b^4*c^(3/2)*d^4*e - 204*a*b^2*c^(5/2)*d^4*e + 54*(sqrt(c)*x - sqrt(c*x^2 + b*x
+ a))^5*b^2*c*d*e^4 - 72*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^5*a*c^2*d*e^4 + 34*(sqrt(c)*x - sqrt(c*x^2 + b*x
+ a))^3*b^3*c*d^2*e^3 + 264*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^3*a*b*c^2*d^2*e^3 + 180*(sqrt(c)*x - sqrt(c*x
^2 + b*x + a))*b^4*c*d^3*e^2 + 900*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))*a*b^2*c^2*d^3*e^2 + 480*(sqrt(c)*x - sq
rt(c*x^2 + b*x + a))*a^2*c^3*d^3*e^2 - 75*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^4*b^3*sqrt(c)*d*e^4 + 180*(sqrt(
c)*x - sqrt(c*x^2 + b*x + a))^4*a*b*c^(3/2)*d*e^4 - 120*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2*b^4*sqrt(c)*d^2*
e^3 - 432*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2*a*b^2*c^(3/2)*d^2*e^3 + 288*(sqrt(c)*x - sqrt(c*x^2 + b*x + a)
)^2*a^2*c^(5/2)*d^2*e^3 + 15*b^5*sqrt(c)*d^3*e^2 + 206*a*b^3*c^(3/2)*d^3*e^2 + 240*a^2*b*c^(5/2)*d^3*e^2 - 15*
(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^5*b^3*e^5 + 36*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^5*a*b*c*e^5 - 40*(sqrt(
c)*x - sqrt(c*x^2 + b*x + a))^3*b^4*d*e^4 - 48*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^3*a*b^2*c*d*e^4 + 192*(sqrt
(c)*x - sqrt(c*x^2 + b*x + a))^3*a^2*c^2*d*e^4 - 33*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))*b^5*d^2*e^3 - 450*(sqr
t(c)*x - sqrt(c*x^2 + b*x + a))*a*b^3*c*d^2*e^3 - 432*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))*a^2*b*c^2*d^2*e^3 +
120*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2*a*b^3*sqrt(c)*d*e^4 - 78*a*b^4*sqrt(c)*d^2*e^3 - 222*a^2*b^2*c^(3/2)
*d^2*e^3 - 88*a^3*c^(5/2)*d^2*e^3 + 40*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))^3*a*b^3*e^5 - 96*(sqrt(c)*x - sqrt(
c*x^2 + b*x + a))^3*a^2*b*c*e^5 + 66*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))*a*b^4*d*e^4 + 306*(sqrt(c)*x - sqrt(c
*x^2 + b*x + a))*a^2*b^2*c*d*e^4 - 120*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))*a^3*c^2*d*e^4 - 96*(sqrt(c)*x - sqr
t(c*x^2 + b*x + a))^2*a^3*c^(3/2)*e^5 + 111*a^2*b^3*sqrt(c)*d*e^4 + 28*a^3*b*c^(3/2)*d*e^4 - 33*(sqrt(c)*x - s
qrt(c*x^2 + b*x + a))*a^2*b^3*e^5 - 36*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))*a^3*b*c*e^5 - 48*a^3*b^2*sqrt(c)*e^
5 + 32*a^4*c^(3/2)*e^5)/((c^3*d^6 - 3*b*c^2*d^5*e + 3*b^2*c*d^4*e^2 + 3*a*c^2*d^4*e^2 - b^3*d^3*e^3 - 6*a*b*c*
d^3*e^3 + 3*a*b^2*d^2*e^4 + 3*a^2*c*d^2*e^4 - 3*a^2*b*d*e^5 + a^3*e^6)*((sqrt(c)*x - sqrt(c*x^2 + b*x + a))^2*
e + 2*(sqrt(c)*x - sqrt(c*x^2 + b*x + a))*sqrt(c)*d + b*d - a*e)^3)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {1}{{\left (d+e\,x\right )}^4\,\sqrt {c\,x^2+b\,x+a}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((d + e*x)^4*(a + b*x + c*x^2)^(1/2)),x)

[Out]

int(1/((d + e*x)^4*(a + b*x + c*x^2)^(1/2)), x)

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